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12. Surface Areas and Volumes

SEBA Class 10 Maths Chapter 12. Surface Areas and Volumes

Chapter 13. Surface Areas and Volumes

 Class 10 Maths Chapter 13. Surface Areas and Volumes Multiple Questions and Solution:

Question : The surface of a cube is  . The length of each edge is : [SEBA 2021]

(a) 15 m    (b) 10 m    (c) 8 m    (d) 5 m

Solution :  (b) 10 m              

[  let  be the length of the cube .

A/Q, 

 ]

Question : If the surface are of a cube is  . then its volume is : [SEBA 2023]

(a)     (b)     (c)    (d)

Solution :  (d)

[  let  be the length of the cube .

A/Q, 

The volume of the cube ]

Question : The volume and surface area of a sphere are equal , then the diameter of the sphere is : [SEBA 17]

(a)  3 units    (b)  6 units   (c) 2 units  (d) 4 units    

Solution:  (b)  6 units

[  We have ,  

 

   units 

units  ]

Question : Two identical cubes each of volume 64 are joined together end to end ,then the surface area of the resulting cuboid is :  [SEBA 2018 , 20]

  (a)           (b)           (c)        (d)

Solution: (d)

[ let  be the length of the cube .

   A/Q ,

 

For cuboid : Here ,

The surface area of cuboid

 

 

 

Question : The volume of a sphere is   . The radius of the sphere is : [SEBA 2019]

(a) 2 cm                    (c) 4 cm                (c) 6 cm               (d) 8

Solution:   (c)  6 cm

 [ let  be the radius of the sphere .

A/Q ,      

 

 

 

 

 cm       ]

Question : The volume of two spheres are in the ratio  then the ratio of their surface areas is : [SEBA16]

(a)  1 : 2                  (b) 2 : 3             (c) 9 : 16               (d) 16 : 9

Solution:   (d)  16 : 9

[ We have,

 

So,     ]   

Question :  A cuboid whose length , breadth and height are 15 cm , 10 cm and 20 cm respectively ,then its surface area is :

 (a)  1200      (b) 1400      (c)  1300     (d) 3000  

Solution:  (c)  1300   .

 [  Here,   cm , cm  and   cm

The surface area cuboid 

 

 

     ]

Question :  If two solid hemispheres of same base radius  are joined together along their bases, then  curved surface area of this new solid is :

 (a)      (b)       (c)       (d)

Solution:    (a)                    

Question : Twelve solid spheres of the same size are made by melting a solid metallic cylinder of base diameter 2 cm and height 16 cm . The diameter of each sphere is :

 (a) 4 cm             (b) 3 cm          (c) 2 cm          (d) 6 cm

Solution:  (c)  2 cm  

[ let  be the radius of the sphere .

Here ,  cm  and   cm

A/Q , 

 

  

 

  cm

 Therefore , the diameter  cm    ]  

Question : In the given figure, if  and  are radius and height of cylinder, then the total curve surface area of the cylinder is :

                

 (a)         (b)      (c)       (d)     

Solution:   (d)      .

 [ The total CSA of cylinder      ]

Question :  The number of solid spheres, each of diameter 6 cm than can be made by melting a solid metal cylinder of height 45 cm and diameter 4 cm is :    [CBSE 2014 ]

  (a)  3        (b)  5         (c)  4      (d)  6

Solution :   (b)  5

 [ Here, The radius of sphere  cm , the radius of cylinder  cm and  cm

The number of solid spheres  

        ]

Question : A rectangular sheet of paper 40 cm × 22 cm , is rolled to form a hollow cylinder of height 40 cm . The radius of the cylinder (in cm) is :   [CBSE 2014 F]

 (a)  3.5    (b)  7        (c)  8      (d)  5

Solution:    (a)  3.5

[ Here,    cm  ,   cm  and  cm

 Area of rectangular sheet of paper  

 A/Q , 

  

  cm     ]

  Class 10 Surface Areas and Volumes  Fill in the blank :

Question : If a sphere of the radius 7 cm , then the surface area of a sphere is   .

 Solution:   616 cm² .

 [ Here ,  cm 

  The surface area of  the sphere

          ]

Question : The volume of the largest right circular cone that can be cut out from a cube of edge 4.2 cm is    .

Solution:       .

[ Here ,  cm   and   cm

The volume of the largest right circular cone 

  

   

     ]  

  Class 10 Surface Areas and Volumes 2 Marks Questions and Solutions :

Question : A solid is in the shape of a cone standing on a hemisphere with both their radii being equal to 1 cm and the height of the cone is equal to its radius , then find the volume of the solid in terms of   .

Solution:   Here ,  cm

 The volume of the solid  

 

     .

Question : A metallic sphere of radius 4.2 cm is melted and recast into the shape of a cylinder of radius 6 cm . Find the height of the cylinder .

Solution:   let  be the height of the cylinder .

 Here ,  cm   and    cm

 A/Q ,       

  

   

 

    cm

Therefore, the height of the cylinder is 2.744 cm .

Question : Two identical cubes each of volume 125   are joined together end to end ,then find the surface area  of the resulting cuboid .

Solution:   Given ,      

 cm

Here ,  cm   ,  cm     and   

Therefore, the surface area of the resulting cuboid

 

  

           

Question : The surface area of a sphere is 616  . Find its radius .

Solution:   let ,  be the radius of the sphere .

 A/Q  ,   

  

  cm

  cm

 Therefore, the radius is 7 cm . 

Question : How many balls , each of radius 2 cm , can be made from a solid sphere of lead of radius 8 cm ?

Solution:  Here ,   cm   and  cm

 Therefore, number of  the balls 

   

Question : How many spherical bullets each of 6 cm in diameter can be cast from a rectangular block of metal  44 cm × 15 cm × 10 cm ?

Solution:   Here , Radius  cm ,  cm  ,  cm  and   cm

Therefore, the number of spherical bullets  

 

 

 

Question :  If the total surface area of a solid hemisphere is  , find its volume . [ Take  ]    [CBSE 2014]

Solution: let  be the radius of the hemisphere.

A/Q , 

 

 cm  

Therefore, the volume of hemisphere  

    

   

     

 Class 10 Surface Areas and Volumes 4 Marks Questions and Solutions   

Question :  A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter  of the hemisphere is equal to the edge of cube . Determine the surface area of the remaining solid . [SEBA 2023]

Solution: Here, diameter   and Radius

The surface area of the remaining solid = Area of cubical block + Area of hemisphere  – Area of circular top

 

 

Question :  A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2 cm and the diameter of the base is 4 cm. Determine the volume of the toy. [SEBA 2021]

Solution : Here ,   , and

The volume of the toy = volume of the cone + volume of the hemisphere

Question :  A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius . The total height of the toy is 15.5 cm . Find the total surface area of the toy . [SEBA 2016 ,2019,2020]

Solution: For cone :  Radius , Height  cm

The slant height

 12.5 cm

The curve surface area of cone

 

   For hemisphere :

The curve surface area of hemisphere

The total surface area of the toy  

Question : From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out . Find the total surface area of the remaining solid to the nearest  . [SEBA 2017]

Solution:  Here , Diameter , Radius , Height  

 The slant height

 

 

 The total surface area of the remaining solid = C.S.A of cylinder + C.S.A. of cone + Area of circular top

   

 

 

 

  [appro.]

Question :  A wooden article was made by scooping out a hemisphere from each end of a solid cylinder, as shown in given figure . If the height of the cylinder is 10 cm , and its base is of radius 3.5 cm , find the total surface area of the article . 

Solution: Here , Radius Height 

The total surface area of the article = C.S.A. of cylinder + Area of 2 hemisphere

 

 

 

   

Question :  A tent is in the shape of a cylinder surmounted by a conical top . If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent . Also, find the cost of the canvas of the tent at the rate of Rs 500 per  . (Note that the base of the tent will not be covered with canvas)

Solution: Here , Height  , Diameter , Radius and the slant height

The area of the canvas of the tent = Area of the cylinder + C.S. area of cone  

 

 

The cost of the canvas of the tent  .

Question :  A gulab jamun, contains sugar syrup up to about 30% of its volume . Find approximately how much syrup would be found in 45 gulab jamuns , each shaped liked a cylinder with two hemispherical ends with length 5 cm and diameter 2.8 cm (see Fig. 13.15)

     

Solution:  Here,   , and

The volume of a gulab jamuns = The volume of the hemisphere + The volume of the cylinder + The volume of the hemisphere

The volume of 45 gulap jamuns

The volume of gulap jamun contains in sugar syrup

Question : A pen stand made of wood is in the shape of a cuboid with four conical depressions to hold pens . The dimensions of the cuboid are 15cm by 10cm by 3.5 cm . The radius of each of the depressions is 0.5 cm and the depth is 1.4 cm . Find the volume of wood in the entire stand .

     

Solution: For cuboid : Here , length  cm , breadth  cm , height  cm

The volume of a cuboidal wood

 

For cone : Here , and

 The volume of a  cone

The volume of  4 cone

Therefore, the volume of wood in the entire stand

  

Question :  A vessel is in the form of an inverted cone . Its height is 8 cm and the radius of its top , which is open, is 5 cm . It is filled with water up to the brim . When lead shots, each of which is a sphere of radius 0.5 cm are dropped into the vessel , one-fourth of the water flows out . Find the number of lead shots dropped in the vessel .

Solution:  For cone : Here, Height of cone  cm  and Radius  cm

  The volume of cone

  For Sphere :  Here,  Radius  cm 

  The volume of the sphere

 The volume of the water that flows out of the cone

(the volume of the cone)                

 Therefore, the number of lead shots

Question :  A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm , which is surmounted by another cylinder of height 60 cm and radius 8 cm . Find the mass of the pole , given that 1 cm³ of iron has approximately 8g mass . (Use )

Solution :  For big cylinder : Here ,  Diameter  , Radius and Height

The volume of the big cylindrical pole

 

 

For small cylinder : Here ,

 Radius , Height

The volume of the big cylindrical pole

 

 

The volume of solid pole

The mass of the pole