1. Find the radian measures corresponding to the following degree measures:
(i) 25° (ii) – 47°30′ (iii) 240° (iv) 520°
Solution: (i) 25°
We have,
(ii)
We have,
(iii) 240°
We have,
(iv) 520°
We have,
2 . Find the degree measures corresponding to the following radian measures (Use ).
(i) (ii) – 4 (iii) (iv)
Solution: (i)
We have,
Solution: (ii) – 4
We have,
[approx]
Solution: (ii)
We have,
Solution: (iv)
We have,
3. A wheel makes 360 revolutions in one minute. Through how many radians does it turn in one second?
Solution: The number of revolution in one minute
Now , one revolution
So, 6 revolution
4. Find the degree measure of the angle subtended at the centre of a circle of radius 100 cm by an arc of length 22 cm (Use ).
Solution: Here, ;
We know that,
We have,
5. In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.
Solution: Here, , and
We know that , the length of minor arc of the chord
6. If in two circles, arcs of the same length subtend angles 60° and 75° at the centre, find the ratio of their radii.
Solution: For first circle : let and are the radius and the arc length of the circle .
.
For second circle : let and are the radius and the arc length of the circle .
[ ]
So,
7. Find the angle in radian through which a pendulum swings if its length is 75 cm and the tip describes an arc of length (i) 10 cm (ii) 15 cm (iii) 21 cm
Solution: (i) Here, ,
We know that ,
(ii) Here, ,
We know that ,
(iii) Here, ,
We know that ,
Find the values of other five trigonometric functions in Exercises 1 to 5.
1.If lies in third quadrant,find the values of other five trigonometric functions .
Solution: We have, (i.e., third quadrant)
Since lies in third quadrant, is negative.
2. If lies in second quadrant.,find the values of other five trigonometric functions .
Solution: We have, (i.e., second quadrant.)
Since lies in second quadrant, will be negative.
Therefore,
3. If lies in third quadrant,find the values of other five trigonometric functions .
Solution: We have, (i.e., third quadrant)
4. If lies in fourth quadrant,find the values of other five trigonometric functions .
Solution: We have, (i.e., fourth quadrant.)
5. If lies in second quadrant,find the values of other five trigonometric functions .
Solution: We have, (i.e., second quadrant.)
Therefore,
Find the values of the trigonometric functions in Exercises 6 to 10.
6.
Solution: We have,
7.
Solution: We have,
8.
Solution: We have,
9.
Solution: We have,
10.
Solution: We have,
1. Prove that:
Solution: LHS :
RHS Proved.
2.Prove that :
Solution: LHS :
RHS Proved.
3. Prove that :
Solution: LHS :
RHS Proved.
4. Prove that :
Solution: LHS :
RHS Proved.
5. Find the value of: (i) sin 75° (ii) tan 15°
Solution: (i) We have,
(ii) tan 15°
We have,
6. Prove that:
Solution: LHS :
RHS Proved.
7. Prove that:
Solution: LHS:
RHS Proved.
8. Prove that:
Solution: LHS :
RHS Proved.
9. Prove that:
Solution: LHS :
RHS Proved.
10. Prove that:
Solution:
LHS :
RHS Proved
11. Prove that:
Solution: LHS :
RHS Proved.
12.Prove that:
Solution: LHS :
RHS Proved.
13. Prove that :
Solution: LHS :
RHS Proved.
14.Prove that:
Solution: LHS :
RHS Proved.
15. Prove that:
Solution: LHS :
RHS :
LHS = RHS Proved.
16.Prove that:
Solution: LHS :
RHS Proved.
17.Prove that:
Solution: LHS :
18.Prove that:
Solution: LHS :
RHS Proved.
19. Prove that:
Solution: LHS :
RHS Proved.
20. Prove that:
Solution: LHS :
21. Prove that:
Solution: LHS :
RHS Proved.
22. Prove that:
Solution: We have,
Proved .
23. Prove that:
Solution: LHS :
RHS Proved.
24.Prove that:
Solution: LHS :
RHS
25.Prove that:
Solution: LHS:
RHS Proved.
Find the principal and general solutions of the following equations:
1. 2. 3. 4.
Solution: 1.
We have,
Therefore, the principal value is .
We know that,
So,
Therefore, the general value is .
Solution: 2.
We have,
Therefore, the principal value is .
We know that,
So,
Therefore, the general value is .
Solution: 3.
We have,
Therefore, the principal value is .
We know that,
So,
Therefore, the general value is
Solution: 4.
We have,
Therefore, the principal value is .
We know that,
So,
Therefore, the general value is
Find the general solution for each of the following equations:
5. 6. 7. 8. 9.
5. Solution: We have,
or
Therefore, the general solution are and .
6. Solution: We have,
or
Therefore, the general values are and .
7. Solution: We have,
or
Therefore, the general values are and .
8. Solution: We have,
Therefore,
Therefore, the general values are and .
9. Solution: We have,
Or
Therefore, the general values are and .
1. Prove that:
Solution: LHS :
RHS
2. Prov that :
Solution: LHS :
RHS
3. Prove that :
Solution : LHS :
RHS Proved.
4. Prove that
Solution: LHS :
RHS Proved.
5.Prove that :
Solution: We have,
RHS Proved.
6. Prove that :
6. Prove that :
Solution: LHS :
RHS Proved.
7. Prove that :
Solution: LHS :
RHS Proved.
8. If lies in second quadrant, find the values of and .
Solution: We have,
(i.e., second quadrant.)
Since ,
So, (i.e., first quadrant.)
Again,
and
9. If in quadrant III , find the values of and .
Solution:
Solution: We have,
(i.e., third quadrant.)
So,
Since,
So, (i.e., second quadrant.)
10. If in quadrant II, find the values of and .
Solution: Since, in quadrant II.
i.e.,
We have,
[ Rationalise]
So, (i.e., first quadrant .)