Evaluate the determinants in Exercises 1 and 2 .
1.
Solution: We have,
2. (i) (ii)
Solution: (i) We have
3. If , then show that .
Solution: Given
Again,
Proved.
(ii) We have,
4. If , then show that .
Solution: We have,
Again,
Therefore, Proved
5. Evaluate the determinants :
(i) (ii) (iii) (iv)
Solution: (i) We have,
(ii) We have,
(iii) We have,
(iv) We have,
6. If , find .
Solution: We have,
7. Find values of , if
(i) (ii)
Solution: (i) We have,
(ii) We have,
8. If , then is equal to
(A) 6 (B) (C) – 6 (D) 0
Solution: We have,
The correct answer (B) ± 6 .
1. Find area of the triangle with vertices at the point given in each of the following :
(i) (1, 0), (6, 0), (4, 3) (ii) (2, 7), (1, 1), (10, 8)
(iii) (–2, –3), (3, 2), (–1, –8)
Solution: We know that the area of the triangle whose vertices are , and is given by
(i) (1, 0), (6, 0), (4, 3)
Here, , , , , ,
We have,
Square units.
(ii) (2, 7), (1, 1), (10, 8)
Here, , , , , ,
We have,
(iii) (–2, –3), (3, 2), (–1, –8)
Here, , , , , ,
We have,
Square units.
2. Show that points A (a, b + c), B (b, c + a), C (c, a + b) are collinear.
Solution: Here, , , , , ,
We have,
Therefore, the points A (), B (), C () are collinear.
3. Find values of k if area of triangle is 4 sq. units and vertices are :
(i) (k, 0), (4, 0), (0, 2) (ii) (–2, 0), (0, 4), (0, k)
Solution: (i) (k, 0), (4, 0), (0, 2)
Here, , , , , ,
We know that ,
or
Therefore, the value of K are 0 and 8 .
(ii) (–2, 0), (0, 4), (0, k)
Here, , , , , ,
We know that,
Therefore, The value of K are 0 and 8 .
4. (i) Find equation of line joining (1, 2) and (3, 6) using determinants.
(ii) Find equation of line joining (3, 1) and (9, 3) using determinants.
Solution: (i) Let be any point on the line joining (1,2) and (3,6) .
Here, , , , , ,
We know that,
Therefore, the equation is .
(ii) Let be any point on the line joining (3,1) and (9,3) .
Here, , , , , ,
We know that,
Therefore, the equation is .
5. If area of triangle is 35 sq units with vertices (2, – 6), (5, 4) and (k, 4). Then k is
(A) 12 (B) –2 (C) –12, –2 (D) 12, –2
Solution: Here, , , , , ,
We know that,
Therefore, the value of k are – 2 and 12 .
Write Minors and Cofactors of the elements of following determinants :
1. (i) (ii)
Solution: (i)
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Now, Cofactor of is .
So,
(ii)
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Now, Cofactor of is .
So,
2. (i) (ii)
Solution: (i) We have,
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Now, Cofactor of is .
So,
(ii) We have,
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Minor of an element is .
Now, Cofactor of is .
So,
3. Using Cofactors of elements of second row , evaluate .
Solution: We have,
Here, , ,
The cofactor of
The cofactor of
The cofactor of
4. Using Cofactors of elements of second row , evaluate .
Solution: Here, , ,
The cofactor of
The cofactor of
The cofactor of
5. If and is Cofactors of , then value of is given by
(A)
(B)
(C)
(D)
Find adjoint of each of the matrices in Exercises 1 and 2 .
1. 2.
Verify in Exercise 3 and 4
3. 4.
Find the inverse of each of the matrices (if it exists) given in Exercises 5 to 11.
5. 6. 7. 8. 9. 10.
11.
12. Let and B . Verify that .
13. If A , Show that . Hence find .
14. For the matrix A , find the numbers and such that .
15. For the matrix A . Show that . Hence , find .
16. If A . Verify that and hence find .
17. Let A be a non-singular square matrix of order 3×3 . Then is equal to
(A) (B) (C) (D)
18. If A is an invertible matrix of order 2 , then is equal to :
(A) (B) (C) 1 (D) 0
Examine the consistency of the system of equations in Exercises 1 to 6.
1. x + 2y = 2 ; 2x + 3y = 3
2. 2x – y = 5 ; x + y = 4
3. x + 3y = 5 ; 2x + 6y = 8
4. x + y + z = 1 , 2x + 3y + 2z = 2 , ax + ay + 2az = 4
5. 3x–y – 2z = 2 , 2y – z = –1 , 3x – 5y = 3
6. 5x – y + 4z = 5 , 2x + 3y + 5z = 2 , 5x – 2y + 6z = –1
Solve system of linear equations, using matrix method, in Exercises 7 to 14.
7. 5x + 2y = 4 ; 7x + 3y = 5
8. 2x – y = –2 ; 3x + 4y = 3
9. 4x – 3y = 3 ; 3x – 5y = 7
10. 5x + 2y = 3 , 3x + 2y = 5
11. 2x + y + z = 1 , x – 2y – z = , 3y – 5z = 9
12. x – y + z = 4 ; 2x + y – 3z = 0 , x + y + z = 2
13. 2x + 3y +3 z = 5 , x – 2y + z = – 4 , 3x – y – 2z = 3
14. x – y + 2z = 7 , 3x + 4y – 5z = – 5 , 2x – y + 3z = 12
15. If A , find . Using solve the system of equations
2x – 3y + 5z = 11
3x + 2y – 4z = – 5
x + y – 2z = – 3
16. The cost of 4 kg onion, 3 kg wheat and 2 kg rice is Rs 60. The cost of 2 kg onion, 4 kg wheat and 6 kg rice is Rs 90. The cost of 6 kg onion 2 kg wheat and 3 kg rice is Rs 70. Find cost of each item per kg by matrix method.
1. Prove that the determinant is independent of .
2. Without expanding the determinant , prove that .
3. Evaluate:
4. If and are real numbers and , Show that either or .
5. Solve the equation .
6. Prove that:
7. If and , find .
8. Let A . Verify that (i) (ii)
9. Evaluate :
10. Evaluate:
Using properties of determinant in Exercises 11 to 15 , Prove that :
11.
12.
13.
14.
15.
16. Solve the system of the following equations
Choose the correct answer in Exercise 17 to 19 .
17. If are in A.P. then the determinant is
(A) 0 (B) 1 (C) (D)
18. If are non-zero real numbers, then the inverse of matrix is
(A) (B)
(C) (D)
19. Let A , where . Then
(A) (B) (C) (D)