Question : In figure , ,then EC is equal to :
(a) 2 cm (b) 3 cm (c) 5 cm (d) 6 cm
Solution: (a) 2 cm
[ In and we have ,
]
Question: D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm , BD = 3 cm , BC = 7.5 cm and . Then, length of DE (in cm) is :
(a) 2.5 (b) 3 (c) 5 (d) 6
Solution : (b) 3
[ Here, AD = 2 cm , BD = 3 cm , AB = 2 + 3 = 5 cm , BC = 7.5 cm
In and , we have
[Common angles]
[corresponding angles]
[A.A.]
]
Question : In given figure and , then the value of is :
(a) 2.3 cm (b) 2.5 cm (c) 2.4 cm (d) 2.8 cm
Solution : (c) 2.4 cm
[ Here,
In and , we have
]
Question : If , and , then RQ is :
(a) 6 cm (b) 12 cm (c) 10 cm (d) 3 cm
Solution: (b) 12 cm
[ In figure ,
Since , we have
So,
]
Question : In given figure , and , then the length of BN is :
(a) 5 cm (b) 4 cm (c) 2 cm (d) 8 cm
Solution: (a) 5 cm
[ In and , we have
]
Question: In . If and ,then the value of DB is :
(a) 12 cm (b) 24 cm (c) 8 cm (d) 4 cm
Solution: (c) 8 cm
[ In , we have
]
Question: DE is drawn parallel to the base BC of a , meeting AB at D and AC at E . If and CE = 2 cm , then AE is :
(a) 5 cm (b) 4 cm (c) 6 cm (d) 7 cm
Solution: (c) 6 cm
[ In and , We have
We have ,
Again,
]
Question : All circles are . [ congruent / similar]
Answer : Similar .
Question : All squares are . [ similar / congruent ]
Answer : Similar .
Question : All triangles are similar . [ isosceles / equilateral / acute triangle ]
Answer : Equilateral .
Question: Two polygons of the same number of sides are similar , if (a) their corresponding angles are and (b) their corresponding sides are . [congruent / equal / proportional /Similar ]
Answer : Equal , Proportional .
Question : In given figure , and , prove that
Solution: Given, and .
To prove that
Proof : In and , we have
In and, we have
From and , we get
Proved .
Question : Prove that a line drawn through the mid-point of one side of a triangle parallel to another side bisects the third side .
Solution: Given, PQR is a triangle whose and S is a mid-point of the side PQ .
To prove : T is a mid-point of PR .
Proof : In figure,
Since S is a mid-point of PQ , then
In and , we have
and , we get
Thus, T is a mid-point of PR . Proved .
Question : In Fig. 6.18, if and, prove that
Solution: In given figure ,
In and we have ,
Again, and we have ,
and we have ,
Proved .
Question : In Fig. 6.36, and . Show that .
Solution: In given figure,
Since,
So,
PQR is an isosceles triangle .
Again,
[from (i) ]
In and , we have
[Common angle]
[ given]
[SAS]
Question : In Fig. 6.37 , if , show that .
Solution: Given, . Then we show that .
Proof : Since, , We have
and
[SAS] Proved
Question : E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F . Show that .
Solution: Given, E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F .
To prove : .
Proof: In given figure,
In and , we have
[ Opposite angle of the parallelogram ]
[ Alternative interior angle]
[A.A rule] proved.
Question : Diagonals AC and BD of a trapezium ABCD with intersect each other at the point O . Using a similarity criterion for two triangles , show that .
Solution: Given, Diagonals AC and BD of a trapezium ABCD with intersect each other at the point O . Then we show that .
Proof : Given figure ,
In and , we have
[ Vertically opposite angle]
[ Alternative interior angle]
[ Alternative interior angle]
[ AAA similarity criterion]
Proved .
Question : The diagonals of a quadrilateral ABCD intersect each other at the point O such that . Show that ABCD is a trapezium .
Solution: Given, the diagonals of a quadrilateral ABCD intersect each other at the point O such that .Then we show that ABCD is a trapezium .
Construction : We join OP such that .
Proof: In given figure,
In and .
But
and we get,
So, then
ABCD is a trapezium . Proved
Question : In Fig. 6.40 , E is a point on side CB produced of an isosceles triangle ABC with . If and , prove that .
Solution: Given, E is a point on side CB produced of an isosceles triangle ABC with , and .
To prove that .
Proof : In given figure,
In , we have
AB = AC
i. e.
In and , we have
[ Given]
[Third angle]
[ AAA rule ]
Question : ABCD is a trapezium with . E and F are points on non-parallel sides AD and BC respectively such that EF is parallel to AB . Show that .
Solution: Given, ABCD is a trapezium with . E and F are points on non-parallel sides AD and BC respectively such that .
To Prove :
Construction : Join AC to intersect EF at G .
Proof : In given figure,
and and also
In and ( )
So,
In and ( )
So,
From (i) and (ii) , we get
Proved.
Question : If AD and PM are medians of triangle ABC and PQR , respectively where , prove that
Solution: Given, AD and PM are medians of triangle ABC and PQR respectively and .
To prove :
Proof : In figure,
Since , D and M are mid-point of the sides BC and QR .
So, and
Given,
Then,
In and , we have
[ ]
[S.A.S.]
Proved.
Question : Prove that a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, the other two sides are divided in the same ratio .
Solution: Given, a triangle ABC in which a line parallel to side BC intersects other two sides AB and AC at D and E respectively .
To prove : .
Construction : Join BE and CD and also , draw and .
Proof : In figure,
We know that , Area of triangle
and
and
Since, and are on the same base DE and between the same parallels BC and DE.
So,
From , and , we have
Proved.