1. Fill in the blanks using the correct word given in brackets :
(i) All circles are . (congruent , similar)
(ii) All squares are . (similar , congruent)
(iii) All triangles are similar . (isosceles , equilateral)
(iv) Two polygons of the same number of sides are similar, if (a) their corresponding angles are and (b) their corresponding sides are . (equal , proportional)
Solution : (i) similar
(ii) similar
(iii) equilateral
(iv) equal , proportional .
2. Given two different examples of pair of :
(i) similar figures (ii) non-similar figures .
Solution : (i) Similar figures :
(ii) Non-similar figure :
3. State whether the following quadrilaterals are similar or not :
Photo 6.8
1. In Fig. 6.17, (i) and (ii), . Find in (i) and in (ii) .
Solution: (i) Here,
In figure,
In and , we have
(ii) Here,
In figure,
In∆ and , we have
2. E and F are points on the sides PQ and PR respectively of a . For each of the following cases, state whether :
(i) and
(ii) , and
(iii) and
Solution : (i) Here, and
In given figure,
and
So,
(ii) Here, ,and
In given figure,
We have,
and
So ,
(iii) Here, ,and
In given figure,
Now,
and
So,
3. In Fig. 6.18, if and, prove that
Solution: In given figure ,
In and we have ,
Again, and we have ,
and we have ,
Proved .
4. In Fig. 6.19, and, prove that
Solution: Given, and.
To prove that :
Proof : In given figure,
In and , we have
In and, we have
From and , we get
Proved .
5. In Fig. 6.20, and. Show that .
Solution: Given, and . Then we show that .
Proof : In given figure,
In and , we have
In and , we have
From and , we get
Proved .
6. In Fig. 6.21 , A , B and C are points on OP , OQ and OR respectively such that and . Show that .
Solution: Given, A , B and C are points on OP , OQ and OR respectively such that and . Then we show that .
Proof: In figure ,
In and , we have
In and , we have
From and , We get
Proved .
7. Using Theorem 6.1 , prove that a line drawn through the mid-point of one side of a triangle parallel to another side bisects the third side . (Recall that you have proved it in Class IX) .
Solution: Given, PQR is a triangle whose and S is a mid-point of the side PQ .
To prove : T is a mid-point of PR .
Proof : In figure,
Since S is a mid-point of PQ , then
In and , we have
and , we get
Thus, T is a mid-point of PR . Proved .
8. Using Theorem 6.2 , prove that the line joining the mid-points of any two sides of a triangle is parallel to the third side . (Recall that you have done it in Class IX) .
Solution: Given, PQR is a triangle such that S and T are the mid-point of the side PQ and PR respectively .
To prove : .
Proof : In figure ,
Since S and T are the mid-point of the side PQ and PR of the triangle PQR respectively .
and
and we get
Thus, Proved .
9. ABCD is a trapezium in which and its diagonal intersect each other at the point O . Show that .
Solution: Given, ABCD is a trapezium in which and its diagonal intersect each other at the point O . Then we show that : .
Construction : We join OP such that .
Proof : In given figure,
Given, then and .
In and , we have
and , we have
and we get,
Proved .
10. The diagonals of a quadrilateral ABCD intersect each other at the point O such that . Show that ABCD is a trapezium .
Solution: Given, The diagonals of a quadrilateral ABCD intersect each other at the point O such that .Then we show that ABCD is a trapezium .
Construction : We join OP such that .
Proof: In given figure,
In and .
But
and we get,
So, then
ABCD is a trapezium .
Proved
1. State which pairs of triangle in Fig. 6.34 are similar . Write the similarity criterion used by you for answering the question and also write the pairs of similar triangles in the symbolic form :
Solution: (i) In given figure,
In and , we have
[AAA]
Yes , Angle-angle-angle (AAA similarity criterion) ,
(ii) In given figure,
In and , we have
;
and
Yes , side-side-side (similarity criterion) ,
(iii) In given figure,
In and , we have
;
and
No , and are not similar .
(iv) In given figure,
In and , we have
and
[SAS]
Yes , side-angle-side (similarity criterion) , [SAS]
(v) In given figure,
In and , we have
No , and are not similar .
(vi) In given figure,
Here,
In and , we have
[AAA]
Yes , angle-angle-angle (similarity criterion) , [AAA]
2. In Fig. 6.35 , and . Find and .
Solution: Given, and .
In given figure :
Since, BD is a straight line .
In , we have
Again,
So,
Therefore, , and
3. Diagonals AC and BD of a trapezium ABCD with intersect each other at the point O . Using a similarity criterion for two triangles , show that .
Solution: Given, Diagonals AC and BD of a trapezium ABCD with intersect each other at the point O . Then we show that .
Proof : Given figure ,
In and , we have
[ Vertically opposite angle]
[ Alternative interior angle]
[ Alternative interior angle]
[ AAA similarity criterion]
Proved .
4. In Fig. 6.36, and . Show that .
Solution: In given figure,
Since,
So,
PQR is an isosceles triangle .
Again,
[from (i) ]
In and , we have
[Common angle]
[ given]
[SAS]
5. S and T are points on sides PR and QR of such that . Show that .
Solution: Given, S and T are points on sides PR and QR of such that .
Then we show that .
Proof : In and , we have
[Given]
[ Common angle]
[Third angle ]
[ AAA similarity criterion]
6. In Fig. 6.37 , if , show that . Show that .
Solution: Given, . Then we show that .
Proof : Since, , we have
and
[SAS] Proved
7. In Fig. 6.38, altitudes AD and CE of intersect each other at the point P .
Show that : (i) (ii) (iii) (iv)
Solution: Given, altitudes AD and CE of intersect each other at the point P . Then we show that : (i) (ii) (iii) (iv)
Proof: In given figure,
(i) In and , we have
[ Vertically opposite angle]
[Third angle]
[AAA rule]
Proof: (ii) In and , we have
[Common angle]
[Third angle]
[AAARule]
Proof: (iii) In and , we have
[Common angle]
[Third angle]
[AAA]
Proof: (iv) In and , we have
[Common angle]
[Third angle]
[AAA rule]
8. E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F . Show that .
Solution: Given, E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F .
To prove : .
Proof: In given figure,
In and , we have
[ Opposite angle of the parallelogram ]
[ Alternative interior angle]
[A.A rule] proved.
9. In Fig. 6.39, ABC and AMP are two right triangles , right angled at B and M respectively . Prove that : (i) (ii)
Solution: Given , ABC and AMP are two right triangles , right angled at B and M respectively .
Then we prove that : (i) (ii)
Proof :In given figure,
(i) In and ,we have
[Common angle]
[Third angle]
[AAA rule]
(ii) Since, [AAA rule ]
Proved.
10. CD and GH are respectively the bisectors of and such that D and H lie on sides AB and FE of and respectively . If , show that :
(i)
(ii)
(iii)
Solution: Given, CD and GH are respectively the bisectors of and such that D and H lie on sides AB and FE of and respectively and . Then we show that :
(i)
(ii)
(iii)
Proof : In given figure,
Since, CD and GH are the bisectors of and respectively .
and
(i) In and we have
[ ]
[ ]
[AA]
Proved.
(ii) Proof: In and , we have
[ ]
[ ]
[Third angle]
[AAA similarity criterion ]
(iii) Proof: In and , we have
[ ]
[ ]
[Third angle ]
[AAA Similarity criterion]
11. In Fig. 6.40 , E is a point on side CB produced of an isosceles triangle ABC with . If and , prove that .
Solution: Given, E is a point on side CB produced of an isosceles triangle ABC with , and .
To prove that .
Proof : In given figure,
In , we have
AB = AC
i. e.
In and , we have
[ Given]
[Third angle]
[ AAA rule ]
12. Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of (see Fig. 6.41) . Show that .
Solution : Given , Sides AB and BC and median AD of a triangle ABC are respectively proportional to sides PQ and QR and median PM of . Then we show that .
13. D is a point on the sides BC of a triangle ABC such that . Show that .
Solution: Given, D is a point on the sides BC of a triangle ABC such that . Then we show that .
Proof: In given figure,
In and , we have
[A.A.A.]
Proved.
14. Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR . Show that .
Solution: Given, Sides AB and AC and median AD of a triangle ABC are respectively proportional to sides PQ and PR and median PM of another triangle PQR .
Then we have to show that ∆ABC ~ ∆PQR .
Construction : We draw and .
Proof : Since , and , then
and [Using mid-point theorem]
Also , X and Y is the mid-point of the sides AB and QR , then
and
We have ,
In and , We have
[SSS]
[CPCT] ………………… (i)
Similarly, we show that …………………. (ii)
Adding (i) and (ii) , we get
In and , we have,
[SAS] Proved .
15. A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long . Find the height of the tower .
Solution : let and are the two triangle .
In given figure,
Here, AB = 6 m , BC = 4 m , PQ = ? and QR = 28 cm
In and , we have
[Same inclination]
[Third angle]
[AAA ]
Therefore, the height of the tower is 42 m .
16. If AD and PM are medians of triangle ABC and PQR , respectively where , prove that
Solution: Given, AD and PM are medians of triangle ABC and PQR respectively and .
To prove :
Proof : In figure,
Since , D and M are mid-point of the sides BC and QR .
So, and
Given,
Then,
In and , we have
[ ]
[S.A.S.]
Proved.